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the perimter of a pentagon is outside of the the pentegon. count what is in the outside

Q: What is the perimter of a pentongon?

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All you have to do is... Add all the sides together! Simples

Many shapes could have a perimeter of 16. A square or rhombus with side = 4, or a rectangle 6 x 2 would have a perimeter of 16. A regular octagon with side length = 2. An isosceles triangle with sides 7, 7 and 2. There are an infinite number of possibilities.

The area is given by xy and the perimter is given by 2x + 2y, where x is the side length and y is the height. So we have two equations: A = xy, P = 2x + 2y. Because the square and the rectangle have the same perimeter, P will be a constant, say 40. We can simplify this to the equivalent 20 = x + y by dividing both sides by 2. We can then rearrange it to y = 20 - x or vice versa for x and y. By substituting this into the first equation, we get A = x(20 - x) = 20x - x2. By using differentiation, we can find the x value for which A is maximum: A' = 20 - 2x Set A' to 0 (we know this will be a maximum because the x2 coefficient is negative): 0 = 20 - 2x 2x = 20 x = 10. Now we back-substitute this value for x into the equation for y: y = 20 - x = 20 - 10 = 10. Thus, the maximum area occurs when x = 10 and y = 10 i.e. when the shape is a square. This works for any starting value of the perimeter, and means that a square will always have more area than any rectangle with an equal perimeter.

Related questions

etyghviugui

It is the sum of its 4 equal sides.

40 cm

add all of the sides together.

measure the distance around the outside

the forumal is to add (sum) all the sides of the polygon.

18

the outside of the shape

Perimeter = 4*1.25 = 5m

All you have to do is... Add all the sides together! Simples

creates rough edges

It is: 4*12 = 48 inches