All you have to do is... Add all the sides together! Simples
Many shapes could have a perimeter of 16. A square or rhombus with side = 4, or a rectangle 6 x 2 would have a perimeter of 16. A regular octagon with side length = 2. An isosceles triangle with sides 7, 7 and 2. There are an infinite number of possibilities.
The area is given by xy and the perimter is given by 2x + 2y, where x is the side length and y is the height. So we have two equations: A = xy, P = 2x + 2y. Because the square and the rectangle have the same perimeter, P will be a constant, say 40. We can simplify this to the equivalent 20 = x + y by dividing both sides by 2. We can then rearrange it to y = 20 - x or vice versa for x and y. By substituting this into the first equation, we get A = x(20 - x) = 20x - x2. By using differentiation, we can find the x value for which A is maximum: A' = 20 - 2x Set A' to 0 (we know this will be a maximum because the x2 coefficient is negative): 0 = 20 - 2x 2x = 20 x = 10. Now we back-substitute this value for x into the equation for y: y = 20 - x = 20 - 10 = 10. Thus, the maximum area occurs when x = 10 and y = 10 i.e. when the shape is a square. This works for any starting value of the perimeter, and means that a square will always have more area than any rectangle with an equal perimeter.
etyghviugui
It is the sum of its 4 equal sides.
40 cm
add all of the sides together.
measure the distance around the outside
the forumal is to add (sum) all the sides of the polygon.
18
the outside of the shape
Perimeter = 4*1.25 = 5m
All you have to do is... Add all the sides together! Simples
creates rough edges
It is: 4*12 = 48 inches