the perimter of a pentagon is outside of the the pentegon. count what is in the outside
Chat with our AI personalities
All you have to do is... Add all the sides together! Simples
Well, isn't that a delightful question! A shape with a perimeter of 16 could be a square with each side measuring 4 units, or a rectangle with dimensions of 3 units by 5 units. Remember, there are many possibilities in the world of shapes, so feel free to explore and create your own unique designs!
The area is given by xy and the perimter is given by 2x + 2y, where x is the side length and y is the height. So we have two equations: A = xy, P = 2x + 2y. Because the square and the rectangle have the same perimeter, P will be a constant, say 40. We can simplify this to the equivalent 20 = x + y by dividing both sides by 2. We can then rearrange it to y = 20 - x or vice versa for x and y. By substituting this into the first equation, we get A = x(20 - x) = 20x - x2. By using differentiation, we can find the x value for which A is maximum: A' = 20 - 2x Set A' to 0 (we know this will be a maximum because the x2 coefficient is negative): 0 = 20 - 2x 2x = 20 x = 10. Now we back-substitute this value for x into the equation for y: y = 20 - x = 20 - 10 = 10. Thus, the maximum area occurs when x = 10 and y = 10 i.e. when the shape is a square. This works for any starting value of the perimeter, and means that a square will always have more area than any rectangle with an equal perimeter.