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Endpoints: (-1, 3) and (-2, -5)

Midpoint: (-3/2, -1)

Slope: 8

Perpendicular slope: -1/8

Perpendicular bisector equation: y --1 = -1/8--3/2 => y = -1/8x -19/16

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6y ago
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6y ago

The perpendicular bisector is 2x + 16y + 19 = 0.

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Q: What is the perpendicular bisector equation of the line segment whose endpoints are at -1 3 and -2 -5?
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