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In order to find the radius of the inscribed circle we have to find the other side'lenght. We will use the property of the right triangle: c^2=a^2+b^2. In our case a = 8 (half of 16 since in this case the altitude is also a median) and b=15 ( the altitude). Using this formula we find that c^2=289 or c=sqrt(289) or c=17. Now that we know all the sides of the triangle we are going to use the following formula r=sqrt[(s-a)(s-b)(s-c)\s] where "r" is the radius of the inscribed circle and "s" is the semiperimeter of the triangle or s=a+b+c\2=16+17+17\2=50\2=25. Now substituting in the formula r=sqrt[(s-a)(s-b)(s-c)\s] we get r=sqrt[(25-17)(25-17)(25-16)\25]=sqrt[8.8.9\25]=sqrt[576\25]=24\5=4,8 . And so we have found the radius of the inscribed circle: r=4,8

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Q: What is the radius of the inscribed circle if the base of an isosceles triangle is 16 inches and the altitude is 15 inches?
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