cos(35)sin(55)+sin(35)cos(55) If we rewrite this switching the first and second terms we get: sin(35)cos(55)+cos(35)sin(55) which is a more common form of the sin sum and difference formulas. Thus this is equal to sin(90) and sin(90)=1
cos(45) = sin(45) You can see this as follows: imagine a circle with radius 1. The point on the circle with angle 45 degrees, lies on the line y=x, equally far from the x-axis (cos) as the y-axis (sin). The angle for both must be 45, because x and y are orthogonal: 90 deg, so if the angle with x is 45, then the angle with y must be 90-45=45. So: for this point, both angles are 45, and the distance to x (cos) is equal to the distance to y (sin). Therefore, cos(45) = sin(45). Additionally, cos(45) = sin(45+90) = sin(45+360n) = sin(135+360n) with n integer.
If sin(theta) is 0.9, then theta is about 64 degrees or about 116 degrees.
False.A function can map several (or even all) values in the domain to a single value in the range. What it cannot do, is to map a single value in the domain to several values in the range. In other words, a function can be many-to-one (or one-to-one) but not one-to-many.One consequence of sin30 = sin150 is that arcsine is not a function unless its range is restricted to -90 to +90 degrees - or some equivalent interval.
90 degrees 90 degrees
On the unit circle sin(90) degrees is at Y = 1 and as that is on the Y axis X will equal = 0. Ask yourself. Where would 90 degrees be on a 360 degree circle? Straight up.
On the unit circle at 90 degrees the 90 degrees in radians is pi/2 and the coordinates for this are: (0,1). The tan function = sin/cos. In the coordinate system x is cos and y is sin. Therefore (0,1) ; cos=0, & sin=1 . Tan=sin/cos so tan of 90 degrees = 1/0. The answer of tan(90) = undefined. There can not be a 0 in the denominator, because you can't devide by something with no quantity. Something with no quantity is 0. Or, on a limits point of view, it would be infinity.
cos(35)sin(55)+sin(35)cos(55) If we rewrite this switching the first and second terms we get: sin(35)cos(55)+cos(35)sin(55) which is a more common form of the sin sum and difference formulas. Thus this is equal to sin(90) and sin(90)=1
5400
In radians; -0.8939966636 In degrees; -1, of course
You do not calculate sin invrse of 50 degrees. You provide a number between -1 and 1 and calculate the sin inverse of that number. The answer you get is usually in radians in you use a calculator which you could convert to degrees if you wish. For example, sin inverse of 1 is 90 degrees. It means sine of 90 degrees is 1. This is how your question would look like. When calculating sin inverse, is the answer in degrees or radians? It is usually in radians but can easily be converted to degrees. Multiply the radians by 180/PI, where PI=3.14159. Example: sin inverse (0.4) = 0.4115 radians which is the same as: (0.4115)(180)/3.14159=23.6 degrees. This means sin of 23.6 degrees is 0.4.
cosecant = 1/sine csc 90 deg = 1/(sin 90 deg) = 1/1 = 1
sin 90 is 1
Assuming you mean -90 degrees, not radians: tan (-90) = [sin(-90)]/[cos(-90)] = (-1) / 0 You cannot divide by zero. tan (-90) is undefined/does not exist.
sin(0) = 0, sin(90) = 1, sin(180) = 0, sin (270) = -1 cos(0) = 1, cos(90) = 0, cos(180) = -1, cos (270) = 0 tan(0) = 0, tan (180) = 0. cosec(90) = 1, cosec(270) = -1 sec(0) = 1, sec(180) = -1 cot(90)= 0, cot(270) = 0 The rest of them: tan(90), tan (270) cosec(0), cosec(180) sec(90), sec(270) cot(0), cot(180) are not defined since they entail division by zero.
I am not sure what "tan A 90 degree" means. tan(90 degrees) is an expression that is not defined and so cannot be solved. One way to see why that may be so is to think of tan(x) = sin(x)/cos(x). When x = 90 degrees, sin(90) = 1 and cos(90)= 0 that tan(90) = 1/0 and since division by 0 is not defined, tan(90) is not defined.
tan(x) = sin(x) /cos(x).When x = 90 degrees then cos(x) = 0 so tan(x) requires division by zero - which is not defined.