45 degree
33
Complementary angles add up to 90°. The complementary angle of 33° is therefore 90 - 33 = 57°.
Yes; if angle of incidence is zero angle of refraction is zero regardless of index: sin theta r = (n1/n2) sin theta i
.33 mayo.fo.sho
sin(37) = 0.6018150232
acute
47
1.836
57o
I need to know how to find each angle measured to the first degree. Such as: Sin B= 0.4848
45 degree
33
I assume your 90 degree angle is on the right and the 30 degree angle is opposite that. ( degree mode ) sin theta = opposite/hypotenuse sin 30 degrees = opp./44 = 22
sin30 is 1/2 or 0.5
sin(30) = 1/2
sin 300 = 1/2