In a general decagon an interior angle can have any value in the range (0, 360) degrees - excluding 180 degrees. The only constraint is that the sum of all interior angles must be 1440 degrees.
The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°
/_3 and /_ 2
A decagon has 10 sides, so it also has 10 angles. Each angle of a decagon is 36 degrees (360 degrees divided by 10). Therefore, a decagon has 10 angles of rotation symmetry.
For a polygon with n sides (n angles), there are (n - 1) remote interior angles for each exterior angle.
Measure of angle 1?
13 1/3 °
The total number of degrees in any regular polygon is calculated by (S-2) * 180º, where S = the number of sides. So, for a decagon the total is 8 * 180º = 1440º, and the measure of each interior angle is 144º, or 1/10th of the total. The last bit is correct only if the decagon is regular. It need not be.
Yes: 1 interior angle plus 1 exterior angle = 180 degrees
It can be any size at all, between zero and 360 degrees.If the nonagon is regular, then the angle measures 140 degrees.
Exterior angle + interior angle = 180 Hence Interior Angle = 180 - Exterior Angle The Exterior Angle = n(No. of sides ) / 360 Substituting Interior Angle = 180 - (n/360) Interior Angle = 180 - (18/360) Interior Angle = 180 - (1/20) Interior Angle = 179.95 degrees.
Each interior angle measures 160 degrees
A right angle triangle can only have 1 right angle of 90 degrees and its 3 interior angles add up to 180 degrees
If you mean 1 acute interior angle, then it's a logical and geometric impossibility.A triangle can't have only one acute interior angle.
The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°
Method 1: EXterior angle of any n-sided polygon = 360/n, in this case 12 so INterior angle is 180 - 12 ie 168o Method 2: Interior angle of any n-sided polygon = ((2n - 4 ) x 90)/n which is (56 x 90)/30 ie 168o.
There are two formulae which can be used for this: 1: As the exterior angles of a regular n-sided polygon are 360/n degrees, the interior angle is 180 less this value; 2: The total of the interior angles of any n-sided polygon is (2n - 4) right angles so in a regular polygon each angle is that value divided by n. In your example n = 10, so by method 1 exterior angles are 36 degrees making the interior angles therefore 144 degrees; By method 2 the total of the interior angles is 16 x 90 ie 1440 degrees, making each angle 1440/10 ie 144 degrees!
/_3 and /_ 2