-6
y = mx + b m = slope = 2 -4= 2(3) + b -4 = 6 + b b = -10 y = 2x -10
slope intercept form is y=mx+b (m is slope, b is y intercept) slope = 4, y intercept = -2 y = 4x -2
You use slope intercept (y=mx+b) to find yourb(y-intercept) 4=-4.5(0) + b 4=b therfore y=-4.5x + 4. Then you change it into standard form (Ax + By = C) y= -4.5x +4 4.5x + y =4 is your answer.
(-4, 6)
slope = 2-(-4)/-2-0 = 2+4/-2 = 6/-2 = - 3 So y=-3x+b Substitute the coordinate (0,-4) -4=-3(0)+b, -4=0+b, -4=b, y intercept is -4 Substitute that for b y=-3x-4 So the answer is y=-3x-4
what is the slope of the line below? (-1,-4) (2.2)
4
-6
The slope of y = 2x - 4 is 2. (y = mx + b, where m is the slope, in this case 2.)
The equation of a line written in slope intercept form has the form of y = mx + b. In this form, m is the slope of the line and b is the y intercept.
Get y by itself in standard form y = mx + b where m = slope and b = y intercept 2x + 4y - 10 = 0 4y = -2x +10 y = -2/4 x + 10/4 y = -1/2 x + 2.5 slope = - 1/2
minus 2 I am starting to see this a lot. The slope intercept form is y=mx+b, where m is the slope and b is the y-intercept. y=-2x+0 the slope (m)= -2, y-intercept (b)= 0
y = mx + b m = slope = 2 -4= 2(3) + b -4 = 6 + b b = -10 y = 2x -10
slope intercept form is y=mx+b (m is slope, b is y intercept) slope = 4, y intercept = -2 y = 4x -2
The standard form eqaution for a line is y = mx + b where m = slope and b is y intercept ( value of y when x = 0) if x = 4 and y = -2 and m = 2 then y = mx + b (eq 1) -2 = 2 (4) + b -2 = 8 + b -10 = b substitute into eq (1): y = 2x-10
b=-2