no, 4x-3y=11x 3x-5y doesn't equal -11
What is the area of a square with a side length of 4x^3
If you meant 4x=3y-120 ==> 4x +120 = 3y ==> 4/3x+40=y In y=4/3x+40 4/3 is the slope (y will be increased by 4 when x is increased of 3) and +40 is the y intercept (when x is zero y is +40)
12x2-x-35 = (4x-7)(3x+5)
4x-2y = 10 -2y = -4x+10 y = 2x-5 which is now in slope-intercept form
4x + 10 + 3x = 40 - 3x 4x + 10 + 3x + 3x = 40 20x = 40 x = 2
3x+5= 4x-10+10 +103x+15= 4x-3x -3x15=X
3x+5 = 4x-10 In algebra, what you do to one side you do the other Now you add 10 to both sides 3x+5 + 10 = 4x-10+10 3x +15 = 4x now subtract 3x from both sides 3x-3x +15 = 4x-3x 15 = x
4x=10+3x or 10+3x=4x
The solution to this problem is x=5.
2 - x > 3x + 102 - x + x > 3x + x + 102 > 4x + 102 - 10 > 4x + 10 - 10-8 > 4x-8/4 > 4x/4-2 > x or x < -2
If you mean: 3x -7 +4x = 28 then the value of x works out as 5
4x - 3x + 7 = -3 x = -3 - 7 = -10
3x + 5 = 4x - 10Add 10 to each side:3x + 15 = 4xSubtract 3x from each side:15 = x
3x - 12 = 10x - 15 - 6x -10 3x - 12 = 4x -25 3x + 13 = 4x 13 = 4x - 3x 13 = x None?
no solution
x + 3x - 10 = 5 - 4 4x - 10 = 1 4x = 1 + 10 x = 11/4