The sum of each pair of interior and exterior angles of a polygon is always 180 degrees.
180
For any polygon: 180-interior angle = exterior angle and the exterior angles of any polygon add up to 360 degrees
Each pair of exterior and interior angles sum to 180 degrees.The sum of all exterior angles of a polygon is 360 degrees.
The sum of the exterior angles of a polygon is 360o. For a regular polygon, these are all equal. For an interior angle of 168o the exterior angle is 180o - 168o = 12o Therefore number of sides = 360o / 12o = 30.
number of sides = 360/exterior angle = 360/120 = 3 polygon is therefore a triangle, interior angles total 180o
360 ________________________________________________ Sum of Interior Angles of a Polygon = 180 (n-2) Sum of Exterior Angles of a Polygon = 360 The sum of an angle and an exterior angle of a regular polygon is 360
No.
180
180
180
For any polygon: 180-interior angle = exterior angle and the exterior angles of any polygon add up to 360 degrees
1440 degrees
The easiest way to solve this is to use the exterior angles of the polygon. The sum of an exterior angle and interior angle is 180o. Also the sum of all the exterior angles of a polygon is 360o. As the polygon is regular, all the interior angles are the same and all the exterior angles are the same. So, for an interior angle of 172o the exterior angle is 180-172 = 8o. The sum of all the exterior angles is 360o so how many 8o make up 360o? 360/8=45. Thus the polygon with interior angles of 172o has 45 sides.
360
1440 degrees
1440 degrees
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.