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What is the sum of the measure of angles in a 75-gon?
Interior angles add up to 13140 degrees
Each interior angle of the regular n-gon has a measure of 175.2 degree find the value of n?
The fastest way to do this one is see that the exterior angle is 180-175.2=4.8° Since all exterior angles must add to 360° or a complete circle, take 360/4.8=75 A regular n-gon has a sum of interior angles equal to 180(n-2). An n-gon also has n angles. Therefore, from the problem statement, 180(n-2) = 175.2n, or n = 360/4.8 = 75.
What is the measure of the vertex angle of an isosceles triangle if one of its base angles measures 75 and its congruent sides each measure 15 cm?
The length of the congruent sides is irrelevant. If one of the base angles is 75 deg, the two base angles sum to 150 degrees. Since the sum of all three angles is 180 degrees, the third angle, the vertex angle, must be 180 - 150 = 30 degrees.
Is it true that a parallelogram can have three angles that measure 75?
no
A triangle has angles of 35 and 75 what is the measure of the third angle?
Always remember that the sum of all the angles in a triangle is always equal to 1800,therefore the third angle is equal to 1800 - (350 + 750 ) = 700
