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What will be the total surface area of a cone whose radius is 2r and slant height is half?
Total surface area = (piradius2)+(piradius*slant length)
What is the surface area of a right cone with slant height of 12 and a radius of 6?
Total surface area: (pi*36)+(pi*6*12) = 339.292 square units rounded to 3 decimal places. That is assuming that you meant the slant length and not the slant height because otherwise you would need to use Pythagoras' theorem to find the slant length.
What is the surface area of a right cone?
Entire surface area of a cone: pi*radius^2 plus pi*radius*slant length
What is the slant height of a cone with a radius of 7 and a altitude of 19?
If you visualize the cone by cutting it vertically (with a plane perpendicular to the base), you can construct a right triangle to represent the radius, altitude, and slant height. This triangle has legs of 7 (the radius) and 19 (the altitude). Its hypotenuse represents the slant height. We can then use the Pythagorean theorem to solve for the slant height: 72 + 192 = s2 72 + 192 = s2 410 = s2 s = √(410) s ≈ 20.24 Therefore the cone has a slant height of √(410), or approximately 20.248456731316586933246902289901 units.
A right cone has a base diameter that is 12 cm and a slant height that is 45 cm What is the surface area of the cone?
Formula for surface area of a cone: π=pi (3.14159265) l=slant height, r=radius. πr2+πrl π62+π6*45=x 36π+270π=x 306π=x 961.33 cm2
