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For an irregular rectangular prism,

the total surface area is BH + (s1 + s2 + s3)L where

B is the base

H the height

L the length

s1 s2 s3 the sides

For a regular triangular prism,

the total area is 3 BL + BH

(The sides are 3 x base x length. The ends are 2 x 1/2 base x height.)
first of all its not triangular prism

its a prism whose base is a triangle

lateral surface area = perimeter of the base (sum of sides of the triangular base) x height(length) of the prism

total surface area = lateral surface area + 2 x area of base

for area of base use the formula

{whole root over [s(s-a)(s-b)(s-c)]}

where a, b, c are the sides of the base triangle

and s = [(a+b+c)/2]

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Q: What is the surface area of a triangular prism?
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