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What is the surface area of the right square pyramid if the height is 11.1 yards and the base is 5.3 yards?
Wiki User
∙ 11y ago
Surface Area (S.A.) = Lateral area (L.A.) + Base Area (B)
Since the base of the pyramid is a square, then B = (5.3 yd)2 = 28.09 yd2.
To find L.A., the sum of the four triangular areas with base 5.3 yd, we need to find first their slant height (l) by using the Pythagorean theorem.
l = √[(5.3/2)2 + 11.12] = √(28.09/4 + 123.21) = √[(28.09 + 123.21*4)/4] = (√520.93)/2 yd.
L.A. = 4[(1/2)(5.3√520.93)] = 10.6√520.93 yd2.
S.A. = 10.6√520.93 + 28.09 ≈ 270 yd2.
Wiki User
∙ 11y ago
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