2X + 4Y = 8 The Y-intercept is the place where the line described by the equation crosses the Y-axis. But X=0 everywhere on the Y-axis. So at that point, 4Y = 8, and Y = 2. The X-intercept is the place where the line described by the equation crosses the X-axis. But Y=0 everywhere on the X-axis. So at that point, 2X = 8, and X = 4.
4y-8x = 12 4y = 8x+12 y = 2x+3 So the slope is 2 and the y intercept is 3
11x-4y=32
-9
It works out that the tangent line of y -3x -5 = 0 makes contact with the circle x^2 +y^2 -2x +4y -5 = 0 at the coordinate of (-2, -1) on the coordinated grid.
It works out that the tangent line of y -3x -5 = 0 makes contact with the circle of x^2 + y^2 -2x +4y -5 = 0 at (-2, -1)
2x+4y = -8 4y = -2x-8 y = -1/2x-2 or y = -0.5x-2
2x+4y=8 4y=-2x+8 y=-2/4x+2 M=-2/4 B=2 B=Y Intercept
x-intercept: 6; y-intercept: 3
2x-4y=-8-2x......-2x-4y=-2x-8(-4y)/-4 | (-2x-8)/-4y=1/2x+2
-2x + 4y = -18It's the equation of a straight line with a slope of (1/2) and a y-intercept of (y= -4.5) .
-2x +4y = 8 4y = 2x +8 y = 1/2x +2 Therefore: the y intercept is 2 and the slope is 1/2
X intercept = -4 Y intercept = 2
If 8x + 4y = 16, then y = - 2x + 4 Thus the slope is -2 and the intercept is 4.
4y - 8x + 12 = 0 4y = 8x - 12 y = 2x - 3 So the slope = 2 y-intercept = -3
2x + 3y = 17 3x + 4y = 24 (2x + 3x) + (3y + 4y) = (17 + 24) 5x + 7y = 41
4y-8x+12 = 0 4y = 8x-12 y = 2x-3 The slope is 2 and the y intercept is -3
I believe that it's 6.