Suppose the specified line has gradient m. Also suppose the specified distance is d.Then x = sqrt[d2/(1 + m2)] and y = m*x.
A translation, by a distance x in the horizontal direction and y=mx in the vertical direction will move the point by the specified distance in the direction of the specified line.
Parallel lines are the same distance apart for all points along the line.
For two coordinates points (x1, y1) and x2, y2), you can find the straight line distance using the Pythagorean theorem.The vertical difference (y1-y2) forms one side of the triangle, and the horizontal difference is the other (x2-x1). The hypotenuse is the straight distance along the line, and is defined by :h = square root of (a2 plus b2) = square root of [ (y2-y1)2 + (x2-x1)2 ]---EXAMPLE :For points (1, 3) and (4, 7), the distance along y is (7-3) and along x is (4-1) andsquare root [ 42 + 32 ] = sq rt [9 + 16] = sq rt [25] = 5.Measuring the distance along the line would verify that the distance is 5.
i searched for this myself but when i drew what they were asking it was pretty obvious that the answer was a diameter. hope this will help.
In a way it does because it means straight lines that remain equal distance apart and never intersect with each other.
In Euclidean space, they could intersect along their whole lengths (in the lines are identical), at a point if they are coplanar and not parallel, or nowhere if they are parallel or skew.
The transformation described is known as a translation. In a translation, each point of a shape or object is moved a specified distance in a direction parallel to a given line. This results in the entire shape retaining its orientation and size while being repositioned in the coordinate plane.
Yes, in geography, all points along a parallel of latitude are indeed the same distance from the equator. This is because parallels are imaginary lines that run parallel to the equator, maintaining the same distance from it as they wrap around the Earth.
Parallel lines are the same distance apart for all points along the line.
The locus of points equidistant from two intersecting lines forms two angle bisectors of the angles created by the lines. When considering points that are at a given distance from a point O, the result is the intersection of the angle bisectors with a circle (or circles) centered at O with the specified radius. This results in two arcs for each angle bisector, forming a total of four distinct points along the angle bisectors, each at the specified distance from point O.
The term for a distance that remains consistent all along is "equidistant." In geometry, points that are equidistant from a common point form a circle, while in other contexts, it can refer to parallel lines or equal spacing between objects. Essentially, equidistant describes a uniform distance maintained throughout.
You've specified a distance, but no force. Any answer is correct without a force specified.
yes....O_o k12
Parallel lines fits the given description.
The equator.
Translatory motion is the motion of an object where all points on the object move along parallel paths in a straight line. It does not involve any rotation, with all points of the object moving the same distance in the same direction. Examples of translatory motion include a car moving along a straight road and an elevator moving up and down a shaft.
The locus of all points that are the same distance from two given points is a perpendicular bisector of the line segment connecting those two points. This line is equidistant from each of the two points at all locations along its length.
The distance between two points on a line is the absolute value of the difference between their coordinates. This can be calculated using the distance formula: |x2 - x1|, where x1 and x2 are the coordinates of the two points.