pentagon
10 triangles....
If the pentagon is a regular pentagon, then each of the central angles (formed by joinning the center with the vertices) is72⁰ (1/5 of 360⁰). So that 5 congruent isosceles triangle are formed, with base angles of 54⁰. If we draw the height, of these triangles (from the center to the sides of the pentagon), 10 congruent right triangles are formed. Let denote with: b the sides of the pentagon, and h the height. In one of the right triangles we have: tan 54⁰ = h/(b/2) tan 54⁰ = 2h/b 1.38 = 2h/b 2h = 1.38b h = (1.38/2)b h = .69b So that, h/b = .69b/b = .69
Complementary angles add up to 90 degrees. If congruent then: 45+45=90
30, its a combination. C(6,3) because there are six vertices of a hexagon and three vertices of a triangle
There are two types of quadrilaterals that are formed when two congruent equilateral triangles are joined. These shapes are rhombus and parallelogram.
13 triangles will be formed
There are 48 triangles that can be formed because 6 triangles can be formed usin each point multiplied by 8.
10 triangles....
Eight triangles.
It is a case of Trigonometry/Geometry. The two triangles formed by the angles and sides of artillery aiming are "Similar" (not congruent) since two angles and a side (base) are Similar. Because the Range of the projectile is 2x the base (which is congruent) of the triangles, the range MUST be the same.
1. Opposite angles congruent 2. All sides are congruent 3. The diagonals are perpendicular bisectors of each other 4. Diagonals bisect the angles NOTE: Four congruent right triangles are formed with the right angles It has all of the properties of a parallelogram and a kite
Two congruent triangles.
Figure that are congruent are shapes are the same size and shape. So when two formed congruent triangles are both together they fit just right.
Angles that are pairs of opposite and congruent lines formed by intersecting lines are intersections
vertical angles are always congruent...they are two nonadjacent angles formed by intersecting lines. Vertical angles are congruent..or equal in measure
If the triangles are congruent and you match the hypotenera the right way, you can get a rectangle. If the triangles are not congruent, you can't even necessarily get a quadrilateral.
If the pentagon is a regular pentagon, then each of the central angles (formed by joinning the center with the vertices) is72⁰ (1/5 of 360⁰). So that 5 congruent isosceles triangle are formed, with base angles of 54⁰. If we draw the height, of these triangles (from the center to the sides of the pentagon), 10 congruent right triangles are formed. Let denote with: b the sides of the pentagon, and h the height. In one of the right triangles we have: tan 54⁰ = h/(b/2) tan 54⁰ = 2h/b 1.38 = 2h/b 2h = 1.38b h = (1.38/2)b h = .69b So that, h/b = .69b/b = .69