169 degrees is an obtuse angle because it is greater than 90 but less than 180 degrees
Providing that it is a regular 35-agon then its interior angles add up to 5940 degrees and each interior angle is 5940/35 = 169.'714285' degrees recurring decimal '714285'
The square root of 169 is ±13. There is point in putting that back in radical form to √169, is there?
The perimeter of a square with an area of 169 cm2 is: 52 cm
Side of a square= take out the square root Area=169cm ² Square root of 169= 13 Side= 13 cm²
169 degrees is an obtuse angle because it is greater than 90 but less than 180 degrees
it should be 169
169 degrees
Use the sine ratio: 13*sin 600 = 11.25833025 or 11.26 units to two decimal places. Incidentally the third side is 6.499999998 units Check using Pythagoras: 11.258330252+6.4999999982 =169 and the square root of 169 is 13 units
Suppose the polygon has n sides. Then sum of the interior angles is (n-2)*180 degrees. Also, each angle is 169 degrees so their sum is 169*n degrees. That is, 180*n - 360 = 169*n or 11*n = 360 which has no integer solution. And, since a polygon, regular or not, cannot have a fractional number of sides, the question does not have a valid answer.
169 is not a prime number. it can be divided by 13. 169 / 13 = 13. so actually 13 would be the square root of 169.No, it is 13 x 13
169 + 169 = 338
169 times 169 equals = 28561
Yes because 12 divided by tan(67.38013505) equals 5 And: 122+52 = 169 making the hypotenuse of the right angle triangle 13 cm
25% of 169 = 42.25= 25% * 169 = 25%/100% * 169 = 0.25 * 169 = 42.25
169 = 1 x 169, or 169 = 13 x 13
25% of 169 = 42.25= 25% * 169 = 25%/100% * 169 = 0.25 * 169 = 42.25