answersLogoWhite

0

Pie/2

=22/7/2

Angle in radians =

Total length of the arc/radius of the circle

User Avatar

Anonymous

5y ago

What else can I help you with?

Related Questions

A rod of length L has total charge Q distributed uniformly along its length it's then bent in the shape of a semicircle find the magnitude of the electric field at the centre of semicircle?

At the center of the semicircle, the electric field due to the straight part of the rod will cancel out because of the symmetry. The electric field at the center of the semicircle is only due to the curved part, so you can treat the semicircle as an arc of a circle with charge distributed along its length. You can then calculate the electric field using the formula for the electric field of a charged arc of a circle.


Half of a circle?

A semicircle is half of a circle, formed by cutting a circle along its diameter line. It has the same curved edge as a circle but only covers half the area. The formula for the area of a semicircle is 1/2 times π times the radius squared.


What word mean half circle?

The word that means half circle is "semicircle." A semicircle is a two-dimensional shape formed by cutting a whole circle along its diameter, resulting in a shape that encompasses 180 degrees of the circle.


What is a figure that has one straight line?

A semicircle is an example of a figure with one straight line. It is a circle that has been split along the diameter.


What is a 3d semi circle caalled?

A 3D semicircle is called a semicircular cylinder or a half-cylinder. It consists of a curved surface and two flat circular faces, where the curved surface is a semicircle extended along a straight line. This shape is commonly found in various applications, including architecture and engineering.


The direct distance between city A and city B?

Is along the arc of the Great Circle which is an imaginary circle with its centre at the centre of the earth and the two cities on its circumference. This is why the direct routes between some cities go over the pole rather than follow latitudes.


What is the electric field at a point outside a nonuniform semicircle of charge?

The electric field at a point outside a nonuniform semicircle of charge is not constant and varies depending on the distribution of charge along the semicircle. The electric field can be calculated using the principle of superposition, taking into account the contributions from each element of charge along the semicircle. The direction and magnitude of the electric field at a specific point can be determined by integrating the contributions of all the charge elements.


What is the center of mass of semicircle?

The center of mass of a uniform semicircle lies along its axis of symmetry, which is the vertical line through its flat edge. Specifically, for a semicircle of radius ( R ), the center of mass is located at a distance of ( \frac{4R}{3\pi} ) from the flat edge along the vertical axis. This position accounts for the distribution of mass in the semicircular shape.


An ion in a mass spectrometer follows a semicircular path of radius 15.2 cm What is the magnitude of the displacement?

The magnitude of the displacement of an object that has traveled in a semicircle (a half circle) is not the DISTANCE that it traveled, but the shortest distance between it's starting point and it's ending point. This means that the diameter of the semicircle = the displacement, so 15.2*2=30.4 cm is the answer.


What is a line that intercects a circle at one point?

Generally, the equation of a circle is (x-a)2 + (y-b)2 = r2where (a,b) is the centre of a circle, and r is the radius.So you can use this equation along with a general line equation, y=mx+c, or using the gradient and finding the equation of the normal.


How do you find out the displacement of a semicircle?

To find the displacement of a semicircle, you can calculate its area and use that to determine the center of mass. The area of a semicircle is given by the formula ( A = \frac{1}{2} \pi r^2 ), where ( r ) is the radius. The center of mass for a semicircle lies along the vertical axis at a distance of ( \frac{4r}{3\pi} ) from the flat edge. By using these values, you can find the displacement in terms of both area and center of mass position.


What is a point that is the same distance from each point?

It's the middle point of line. Hardly! How far would that be from a point 3/4 way along the line? Try centre of a circle, or of a sphere.