A cylinder, a frustum, a sphere with two slices cut off, a torus (doughnut) with a wedge removed are some examples.
They are called a Vertices and it is where 2 edges meet.
The question is ambiguous. An octagon is a 2-dimensional shape with 8 edges and 8 vertices. Does a 3-D octagonal shape mean one with 8 edges or 8 faces or vertices, or faces which are 2d octagons?
Well, honey, that sounds like a hexagonal prism to me. It's got those six faces, six vertices, and ten edges, making it the life of the 3D shape party. So, go ahead and strut your stuff with that hexagonal prism knowledge!
There can be no such shape.
A cuboid seems to fit the given description because it has 6 faces, 12 edges and 8 vertices.
They are called a Vertices and it is where 2 edges meet.
# of faces + # of edges + # of vertecies + 2
According to Euler none; for all 3d shapes: Vertices + Faces = Edges + 2 ⇒ 12 + 8 = 19 + 2 ⇒ 20 = 21 So unless 20 does equal 21, no 3d shape has 8 faces, 19 edges and 12 vertices. Any 3d shape with 8 faces would be an octahedron.
sphere
i would say a cube
The question is ambiguous. An octagon is a 2-dimensional shape with 8 edges and 8 vertices. Does a 3-D octagonal shape mean one with 8 edges or 8 faces or vertices, or faces which are 2d octagons?
Their relationship is modelled by the equation F + V = E + 2, where F is the number of faces, V is the number of vertices, and E is the number of edges.
Faces= 2 edges=5 vertices=12 Faces= 2 edges=5 vertices=12
Well, honey, that sounds like a hexagonal prism to me. It's got those six faces, six vertices, and ten edges, making it the life of the 3D shape party. So, go ahead and strut your stuff with that hexagonal prism knowledge!
There can be no simply connected polyhedron with the specified number of faces, vertices and edges. The Euler characteristic requires that F + V = E + 2 where F = number of faces V = number of vertices E = number of edges This requirement is clearly not satisfied.
triangular prism
That's an impossible shape. No shape can have only 2 edges.