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Do you mean the following?

(x + 16)2 + (y + 3)2 = 17

(x + 3)2 + (y - 6)2 = 44

You can find the center of these circles by using the negatives of the numbers subtracted by the x and y variables. In this case, the circles are centered at the points (-16, -3) and (-3, 6). The one in which both the x and y co-ordinates are negative would be the one in the third quadrant.

And try to phrase your questions better. That could just as easily be read as "ax + 162 + y + 32 = 17bx + 32 + y - 62 = 44", which makes no sense.

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