For any triangle, it is the sum of the lengths of the sides a, b, and c. (P = a + b + c)For a right triangle, it is a + b + [sq rt (a2 + b2)]for the two sides and the hypotenuse (diagonal).It is the sum of its 3 sides
No. An equiangular triangle is always equilateral. This can be proven by the Law of Sines, which states that sin A / a = sin B / b = sin C / c, where A, B and C are angles of a triangle and a, b and c are the opposing sides of their corresponding angles. If A = B = C, then sin A = sin B = sin C. Therefore for the equation to work out, a = b = c. Therefore the eqiangular triangle is equilateral, and therefore not scalene, which requires that all sides of the triangle be of different lengths.
The perimeter of a triangle is found by adding all 3 sides of the triangle. This is most commonly expressed using the formula for a triangle's perimeter: a+b+c=P. Where P is perimeter and a,b,and c are the three sides.
none. A triangle, in standard 2 dimensions cannot have any parallel sides. Let's show without going into formal proof. Let's say that you try to make a triangle with 2 parallel sides. -------------side a------------- |C | | |side b | | |A -------------side c--------------- Side a & b intersect at vertex C. Side b & c intersect at vertex A, and since sides a & c are parallel, they will never intersect, so there is no third vertex, so it's not a polygon, much less a triangle.
According to the Pythagorean theorem, the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides or, c^2 = a^2 + b^2. Since there is no single value where a = b= c, a right triangle cannot have all equal sides.
If the lengths of the sides are a, b, and c then it is (a + b + c)/2.
Oh but it is possible.If you have a triangle with the three sides labeled 'a', 'b', and 'c' in clockwise order,and you reassemble them in the clockwise order of 'a', 'c', 'b', then the new triangleis not congruent to the original one. It's a different triangle.
For any triangle, it is the sum of the lengths of the sides a, b, and c. (P = a + b + c)For a right triangle, it is a + b + [sq rt (a2 + b2)]for the two sides and the hypotenuse (diagonal).It is the sum of its 3 sides
P = a + b + cyou just add the sides together.Just add up the three sides of the triangle.
No. An equiangular triangle is always equilateral. This can be proven by the Law of Sines, which states that sin A / a = sin B / b = sin C / c, where A, B and C are angles of a triangle and a, b and c are the opposing sides of their corresponding angles. If A = B = C, then sin A = sin B = sin C. Therefore for the equation to work out, a = b = c. Therefore the eqiangular triangle is equilateral, and therefore not scalene, which requires that all sides of the triangle be of different lengths.
you add the sides together . a /\b a+b+c /_\ c
a^2 + b^2 = c^2 c= hypotenuse a and b are the legs (sides) of the triangle
According to the Pythagorean Theorem, if a triangle has one angle that measures 90 degrees (called a "right triangle"), and each of the three sides is labeled a, b, and c (with the only side not touching the 90 degree angle, the hypotenuse, labeled "c"), then: a2 + b2 = c2 In other words, the length of the sum of the squares of two sides equals the square of the length of the hypotenuse.
The perimeter formula of a triangle is the sum of the lengths of all three sides. Mathematically, it can be expressed as P = a + b + c, where P is the perimeter and a, b, and c are the lengths of the three sides of the triangle.
#include<stdio.h> #include<conio.h> void main() { int a,b,c; clrscr(); printf("\n Enter the 3 sides of Triangle: "); scanf("%d %d %d",&a,&b,&c); printf("\nYour entered side is a=%d b=%d c=%d",a,b,c); if(a==b && b==c && a==c) { printf("\n EQUILATERAL TRIANGLE.");//All sides equal in case of Equilateral triangle } else if(a!=b&&b!=c) printf("\n SCALENE TRIANGLE."); //All sides unequal else printf("\n ISOCELES TRIANGLE."); //At least 2 sides equal getch(); }
The sides
There are several. Some of the more common ones are: Any two sides of a triangle must be larger than the third. If a, b and c are the lengths of the sides and A, B and C are the angles oppostie these sides, then sin(A)/a = sin(B)/b = sin(C)/c a2 = b2 + c2 - 2bc*Cos(A)