The tree is 12.5 feet in height
It is not possible to determine the area of a quadrilateral given only the length of its four sides.
Assuming the shape is a triangle, the area is 11.40 sq ft, approx.
if one sides of the garden is 5ft what is the perimeter of the garden
If it was a 5ft by 4ft rectangle then it would be 20ft2. in fact you have a lot of options to make a 20ft2 surface for example: 10ft * 2ft = 20ft2 or 2*51/2ft * 2*51/2ft = 20ft2&etc you can solve your question by this equation x*y=20 then you can find one variable by choising other one y = 20/x If you give x you get y
5ft * 4ft * 3ft = 60 cubic ft = 1.699 cu metres
A square yard is 3ft by 3ft
It is: 4+5+3 = 12 feet
If its sides are 3 by 4 then using Pythagoras its diagonal is 5 feet
if you have a base line of say 10FT then all you have to do is go to your stop point and count back say 3FT then go back to you stop point and go up 4FT then all you have to do is make your 5FT mark from the 3FT to the 4FT and then you should have a right angle...
If by space you mean volume, it is 60 this is simply the product of the height width and depth or 3x4x5
6+4+5+4+6+4+5+4 = 12 + 10 + 16 = 38. 38ft.
Surface area = 2*(3*4 + 4*5 + 5*3) = 2*(12 + 20 + 15) = 2*47 = 94 sq ft.
Two and Four are both common denominators of Four and Eight, therefore either of these can be used. You would need only two 4ft square tiles or eight 2ft square tiles to cover the 4ft x 8ft floor.
60 inches is bigger. 60in = 5ft 48in=4ft
1ft-3ft-5ft
5ft