acute
in a frictionless vacuum, 45°, otherwise (on earth), aim to have the projectile release when the arm is at about 40° from the base
At a 45 degree angle
Good Question. I will explain the best i can.First you lift your leg at a 90 degree angle so if you look at the side of your body its like a "Z".Next you push only the bottom half of your leg out so now it looks like a 45 degree angle of a triangle by a side view.Finally hit the target. =D Hope this was useless.Haha have fun. you just want to put a question on here.
15 degrees.Though the problem uses geometric terminology, it's actually best done with algebra.Knowing that an angle and its complement add to 90, we can express the angle's complement as (90 - x).Similarly, since an angle with its supplement add to 180, we can express the supplement as (180 - x).Now we can put these together to0 create the basis for finding x.(90 - x) + (180 - x) = 240All that's left is to simplify step by step until we get our solution.90 - x + 180 - x = 240270 - 2x = 240-2x = -302x = 30x = 15And to verify, a 15-degree angle has a 75-degree complement and a 165-degree supplement. Sure enough, 75+165=240.
Hello: * Yes, the angle of a catapult does affect the distance. And this applies to both changing the angle of the catapult and changing the angle of the terrain under the catapult. If you shoot the catapult at say 45 degrees, you have very good distance. If you shoot it at 30 degrees, while it may be further, it would be lower to the ground and perhaps not travel as far hitting trees and running into wind-shear. If you shoot at say 80 degrees, while the lob goes high up in the air, it won't travel very far. So your best bet, for maximum distance, is to take your catapult to the highest possible altitude, aim for 45 degrees, taking into account the wind direction and speed, and lob away. Don't hit anyone. :) Answer Actually, the maximum distance that can be achieved from a catapult is at an angle of 45 degrees. Every degree increase from 0 up to 45 approaches the maximum distance that something can be thrown. Every degree from 45 to 90 decreases the distance.
From the top of the key.
A Trebuchet Catapult
acute
Well since an acute angle is everything with a smaller degree than a right angle, there is no perfect acute angle. However, to demonstrate an acute angle, i would go with around a 20-25 degree angle.
in a frictionless vacuum, 45°, otherwise (on earth), aim to have the projectile release when the arm is at about 40° from the base
36
it is a try square
Any triangle with a 90 degree angle is a right triangle.
the best angle is "45 degree" because the air speed coming out of the fan is giving by this equation V=v.tanθ were : V: air speed,,, v: is the blades speed and we got the maximum of the speed by making the angle 45
The best hypothesis for a marshmallow catapult could be: "Increasing the tension in the catapult's elastic band will result in the marshmallow traveling a longer distance." This hypothesis allows for clear testing of the relationship between tension and distance traveled.
Catapults are made from wood!