The [horizontal] range of a projectile is maximised when it shoots at a 45 degree angle. This is true if air resistance is ignored so that the only force acting on the projectile is gravity.
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in a frictionless vacuum, 45°, otherwise (on earth), aim to have the projectile release when the arm is at about 40° from the base
At a 45 degree angle
Good Question. I will explain the best i can.First you lift your leg at a 90 degree angle so if you look at the side of your body its like a "Z".Next you push only the bottom half of your leg out so now it looks like a 45 degree angle of a triangle by a side view.Finally hit the target. =D Hope this was useless.Haha have fun. you just want to put a question on here.
15 degrees.Though the problem uses geometric terminology, it's actually best done with algebra.Knowing that an angle and its complement add to 90, we can express the angle's complement as (90 - x).Similarly, since an angle with its supplement add to 180, we can express the supplement as (180 - x).Now we can put these together to0 create the basis for finding x.(90 - x) + (180 - x) = 240All that's left is to simplify step by step until we get our solution.90 - x + 180 - x = 240270 - 2x = 240-2x = -302x = 30x = 15And to verify, a 15-degree angle has a 75-degree complement and a 165-degree supplement. Sure enough, 75+165=240.