You cannot draw a diagonal from a vertex to itself. So that is 1.
Also, the diagonals to the adjacent vertices on either side will actually be the sides of the polygon, not diagonals. Those are the other 2.
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dont no and need to no does anyone no the answer?
A decagon has 35 diagonals. A Nonagon has 27 diagonals. An Octagon has 20 diagonals. A Heptagon has 14 diagonals. A Hexagon has 9 diagonals. A Pentagon has 5 Diagonals. A Square has 2 Diagonals. A triangle has 0 Diagonals.Do you get the point?0+2+3+4+7+8. Starting with the triangle.you don't need to start with the triangle because it is 0 diagonals and will not count when you add it up anyways. And don't call it a square, call it a quadrilateral.Shut up-------Imagine a hexagone-There are two vertices at the top which make a horizontal line- Opposite them there are 2 vertices on the bottom which we can draw straight lines totherefore-There would have been 6 connections per point, but we eliminated 3(n-3)---The connections occur for every vertex in the shapethereforen(n-3)--We don't want to draw the same connections twice once we get around to vertices on the opposite side of the shapethereforen/2(n-3)where n is the number of facesThis may be applied to many if not all polygons. A Decagon has 36 sides not 35...There are 35 diagonals in a 10 sided decagon
No. A polygon can be symmetric but need not be. In fact, the majority of polygons are not symmetrical.
you stupid that's a easy question go get some help u need to go to a therapist
dont know .................................................................................. joke only we need to study polygons because ........................................ ewan/....................................
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Equiangular (not eqiangular) polygons are equiangular. These can be, but need not be, regular polygons.
They are polygons with six straight sides and six vertices. The sum of the interior angle is 720 degrees. There are 18 diagonals. For almost any other characteristic you would probably need to assume that it is a regular hexagon and there is no justification for such an assumption.
dont no and need to no does anyone no the answer?
A 3-gone does not have diagonals. The two diagonals of a 4-gon meet at a point. For all values greater than 4, the diagonals of an n-gon need not necessarily meet at a single point.
A decagon has 35 diagonals. A Nonagon has 27 diagonals. An Octagon has 20 diagonals. A Heptagon has 14 diagonals. A Hexagon has 9 diagonals. A Pentagon has 5 Diagonals. A Square has 2 Diagonals. A triangle has 0 Diagonals.Do you get the point?0+2+3+4+7+8. Starting with the triangle.you don't need to start with the triangle because it is 0 diagonals and will not count when you add it up anyways. And don't call it a square, call it a quadrilateral.Shut up-------Imagine a hexagone-There are two vertices at the top which make a horizontal line- Opposite them there are 2 vertices on the bottom which we can draw straight lines totherefore-There would have been 6 connections per point, but we eliminated 3(n-3)---The connections occur for every vertex in the shapethereforen(n-3)--We don't want to draw the same connections twice once we get around to vertices on the opposite side of the shapethereforen/2(n-3)where n is the number of facesThis may be applied to many if not all polygons. A Decagon has 36 sides not 35...There are 35 diagonals in a 10 sided decagon
To square a box frame, you need to measure the diagonals of the frame. If the diagonals are equal in length, then the frame is square. If they are not equal, you can adjust the frame by shifting the corners until the diagonals are equal.
One pentagon and five triangles.
Your quesion makes no sense. Please elaborate, and i will do my best to provide an answer. You need to tell me what your are comparing polygons to. Ex: What are 4 thing polygons and CIRCLES have in common. your sentence lacks that.
Isolateral polygons. They need not be regular polygons. For example, a rhombus has all congruent sides but it is not a regular polygon.
Find the midpoint of the two diagonals