360 degrees divided by 5 (sides of a pentagon) gives you 72 degrees.
The sum of all the angles of a figure with n corners is (n*180*-360) triangle: 180 degrees tetragon: 360 degrees pentagon: 540 degrees So each of the inside angles of a regular pentagon measures 540/5=108 degrees. The exterior angle is thus 360-108= 252 degrees.
Answer72 degrees to find the exterior angle of a polygon just divide 360 by the number of sides. so for a pentagon it would be:360 divided by 5 which is 72 degrees
Any individual angle of a pentagon can have any value between 0 and 360 degrees. Their sum must be 540 degrees.
The sum of the exterior angles of a polygon always equal 360 degrees. So...360/18 = 20 degrees
No, the internal angles of a simple pentagon sum to 540 degrees. See: http://en.wikipedia.org/wiki/Pentagon
Because a pentagon has 5 angles and all must be equal, you can divide the total degrees (360) by the number of sides (5) to get the degrees per angle. 360 / 5 = 72 degrees per angle.
360 degrees. The exterior sum of angles of any polygon is always 360 degrees
360
360 degrees divided by 5 (sides of a pentagon) gives you 72 degrees.
you basically do 360 divided by 5 (the sides of a pentagon) which is ...ummm.. 72 degrees
The 5 exterior angles of a pentagon add up to 360 degrees
A regular pentagon has 5 equal sides and 5 equal angles. If each vertex (corner) is joined by a line to the pentagon's centre there are 5 equal angles at the centre, which total 360 degrees. Therefore each one is 360/5 degrees = 72 degrees. The other angles inside the 5 triangles are equal and must total 180 - 72 degrees = 108 degrees. The "external angles" equal the ones at the centre (72 degrees). Now, if a regular figure is to tesselate it must have angles which are simple fractions of 360 degrees, like 10 or 15 or 20 or 30, 40. 45, 60, 90, and angles of 72 or 108 degrees are no use for the purpose.
I think it's because 360 degrees always equals 100%.
360 degrees
360 degrees
An angle in a pentagon can have any value between 0 and 360 degrees.