Start with the equation
y = 2
Put that into slope-intercept form:
y = 0x + 2
Change the y-intercept to 3
y = 0x + 3
or simply
y = 3.
This is a bit of a trick question to see if you understand the terminology. The line y = 2 is parallel to the x-axis, two spaces above it. A line parallel to that would also be parallel to the x-axis, and the intercept of 3 means that it is 3 spaces above the x-axis at the center of the graph. It remains 3 units above the x-axis out to infinity.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
5x-4y=8
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
-7
The slope of x and the y intercept as for example in the straight line equation of y = 2x+3 the slope is 2 and the y intercept is 3
Since the two lines are parallel, then they have the same slope, 3. Thus, the equation of the line with y-intercept -4, and parallel to y = 3x - 3 is y = 3x - 4.
parallel to y=4x-3 so they have the same gradient of 4 y intercept is positive 1 so y=4x+1
The line 'Y = - 3' has a slope of zero. Any line parallel to it also has a slope of zero. The line parallel to it with a Y-intercept of 7 is: Y = 7
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.
find equation of the line. write equation in slope intercept form. (5,5) parallel line (3,13) and (12,13)
y=2/3x-7
y = -x + 8
Write an equation in slope-intercept form for the line that passes through the given point and is parallel to the given line (-7,3); x=4
5x-4y=8
By including the + or - signs in the question
-12