Here is the answer to your query.
Consider two ∆ABC and ∆PQR. In these two triangles ∠B = ∠Q = 90�, AB = PQ and AC = PR.
We can prove the R.H.S congruence rule i.e. to prove ∆ABC ≅ ∆PQR
We need the help of SSS congruence rule.
We have AB = PQ, and AC = PR
So, to prove ∆ABC ≅ ∆PQR in SSS congruence rule we just need to show BC = QR
Now, using Pythagoras theorems in ∆ABC and ∆PQR
Now, in ∆ABC and ∆PQR
AB = PQ, BC = QR, AC = PR
∴ ∆ABC ≅ ∆PQR [Using SSS congruence rule]
So, we have AB = PQ, AC = PR, ∠B = ∠Q = 90� and we have proved ∆ABC ≅ ∆PQR. This is proof of R.H.S. congruence rule.
Hope! This will help you.
Cheers!!!
It's actually angle B angle Y
pfft no, it's AC = DF
AC is congruent to DF.
B=Y
or
C=Z
Line segment BC is congruent to Line Segment YZ
Angle "A" is congruent to Angle "D"
congruent - SSS
Answer by Arteom, Friday December 10, 2010
AAS is equal to angle-angle-side, and is descriptive of a triangle. JKL and MNO would be the sides and angles of a triangle. The two sides must be congruent to the opposite angle.
False. If ABC definitely equals DEF equals MNO and MNO equals PQR then ABC does not equal PQR by the transitive property.
False
Bc= qr
false
It is actually "CORRESPONDING"..
not congruent
Congruent - SSS
k,l n;lm;m
The triangles must be congruent.
angle B angle Y
(Tested, correct)
Nicki is not the answer, just ignore that.
Yes, it does.
i honestly dont know
Nope Congruent - SSS Apex. You're welcome.
ML=YZ ,
__ - __
AC = XZ
True