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((60m/s+80m/s)/2)x12s=840m
It will take a sailboat 24 hours traveling at 5 miles per hour to sail 120 miles.
The average uninformed acceleration is (delta-V) / (delta-T). Delta-V = (96 - 32) = 64 m/s. Delta-T = 8.0 seconds. A = (64 m/s) / (8.0 sec) = 8 m/s2
The hypotenuse is: 10
F=ma
m=F/a
m=20/4.0
m=5Kg
3.229 miles/hour
If a right triangle is 12.5 meters and the side opposite a 30 angle, the hypotenuse length will be: 14.43 meters.
Assuming that his acceleration was linear (ie. that he slowed down at a perfectly steady rate), then you can say his velocity at any point in those eight seconds was:
21 - t(21 / 8) m/s
To get the distance covered in that time, you can simply take the area under that line between 0 seconds and eight seconds. Because it's linear, this is very easy. You're dealing with a right triangle that is 8 seconds wide and 21 meters per second tall. With a triangle, the area is equal to half it's width times it's height, so the equation is:
d = 21m/s * 8s / 2
∴d = 168m / 2
∴d = 84m.
So he traveled 84 meters in those 8 seconds, and probably scared the bejeebers out of that poor deer.
Average speed = 21/2 m/s , Time =8 s, Distance = 8 x 21/2 = 84m
-80/10 = -8 m/s2
milli
60 m/s
Vector, magnitude and direction.
Air miles from Oklahoma City, Oklahoma, to Dallas, Texas, total 191 miles. That is 307 kilometers or 166 nautical miles.
Vector because it has both direction and magnitude.
We are not told if the car just reaches the deer, or gets to some other distance before or past the deer. If it just reaches the deer, it traveled 90 metres of course. From the information supplied it doesn't matter where the deer was.
1
tan(23) = 1.58815308
