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A and B, B and C, C and D, D and A, are all supplementary pairs.
The figure has no complementary pairs of angles.
Answer this question... Which of the following is a true statement about skew lines?
92
vertical angles and supplementary.
What isn't the inverse of this statement(?)
No.
A triangle can be Acute, Obtuse, or Right, depending on the angle. It can be Scalene, Isosceles, or Equilateral, depending on the length of the sides.
It maens that JK meets LM at right angles of 90 degrees
Is PQ |_ RS
Nknvj
which pair of angles in the figure below are vertical angles ?
A plane.
?
Perpendicular lines intersect each other at right angles which is 90 degrees.
The sum of the 4 internal angles of a quadrilateral must sum to 360° (go look up the proof of this elsewhere).
For the sake of argument, let's call the 4 internal angles of a quadrilateral A, B, C, and D.
If they were all obtuse, then (by definition):
180° > A > 90°
180° > B > 90°
180° > C > 90°
180° > D > 90°
If you add them all up, you find that for the sum of the angles A+B+C+D
720° > A + B + C + D > 360°
but, A+B+C+D = 360°,
Since the assumption produces a result that contradicts this, the assumption cannot be true.
Q.E.D.
No, it could not. A triangle cannot have a perimeter of length zero.
T is the midpoint of PQ
angle PTR = 90 degrees
RS _l_ PQ
PT = QT
If the lines AB and CD are parallel then they both will have the same slope of -8 but with different y intercepts
CD
JM
(apex) its 110
