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☆☆☆☆☆Coplanar lines that do not intersect are called parallel lines.
A quadrilateral is an object formed by four straight lines - two of which meet at an angle. A diagonal is one of the lines which go from one angle to the one other angle in the quadrilateral which it is not already connected to.
If the angles of the quadrilateral are A, B, C and D, and A is connected by a straight line to B and D then the diagonal is a line between A and C.
A--B
| \ |
D--C
45
It would be an obtuse triangle with one angle being greater than 90 degrees.
Yep. All equilateral triangles are isosceles triangles.
I got the answer:
if first#=A, second#=B, third#=C, fourth#=D, fifth#=E
The fifth number plus the third number equals fourteen. E+C=14
The fourth number is one more than the second number. D=B+1
The first number is one less than twice the second number. A=(B*2)-1
The second number plus the third number equals ten. B+C=10
The sum of all five numbers is 30. A+B+C+D+E+F=30
Observing, B is present in most clues.
Then use last clue A+B+C+D+E=30
Since E+C=14 just take out E and C then put 14
A+B+D+14=30
A+B+D=30-14
A+B+D=16
Substitute remaining clues
[(B*2)-1] + B + (B+1) = 16
(B*2) -1 + B + B + 1 = 16 -> negative one plus one is zero
(B*2) + 2B = 16
(B*2) = 16 - 2B
B*2 = 2 (8-B)
B*2 = 2 (8-B) -> divide both sides by 2
B = 8 - B
B + B = 8
2B = 8 -> divide both sides by 2 (sorry i know theres a short cut to this hehehe)
B = 4
Apply to clue #2:
D = B+1
D = 4+1
D = 5
then
A + B + C + D + E = 30, where B= 4, D= 5, E+C=14
A + 4 + 14 + 5 = 30
A = 30 - 4 - 14 - 5
A = 7
Using clue # 4
B + C = 10
4 + C = 10
C = 10 - 4
C = 6
Using clue #1
E + C = 14
E + 6 = 14
E = 14 - 6
E = 8
The Answer is 7, 4, 6, 5, 8
Thats it!!!
an interior angle + and exterior = 180 Angle A: 180-30=150 Angle B: 180-60=120 Angle C: 180-90=90 Angle D: 180-120=60 SO WHATS THE ANSWER!!!?????
An isosceles triangle must have two sides of equal size.
Since you have a side of 7 and 5, for it to be isosceles, your third side must be either 7 or 5.
144
3x + 5x + 10 = 0
a = 3, b = 5, c = 10
D = b - 4ac = 25 - 120 = -95
Since D < 0, we have two conjugate complex roots.
√D = √-95 = i√95
x = (- b ± √D)/2a
x = -5/6 + [(√95)/6]i or x = -5/6 -[(√95)/6]i
8 3/4 ft. = 104 inches
12 inches in a foot
8 inches in 3/4 of a foot.
(8 x 12) + 8 = x
96 + 8 = x
x = 104
A and B, B and C, C and D, D and A, are all supplementary pairs.
The figure has no complementary pairs of angles.
The correct answer is C
A) 20-30%
B) 30-40%
C) 40-50%
D )50-60%
E) 60-70%
C f ef a g fg
agf f a cd
dc aa fg fg
agf dd c f
dc aa fg fg
dc aa cd
dc aa fg fg
agf dd c f
A triangle, but only if the line segments are straight.
not all congruent angles are vertical angles. Vertical angles must share a vertex.
Answer is a skew lines do not lie in the same place
vertical and supplementary
3 vertices in a triangle, whether it is equilateral, isosceles or scalene; acute angled, right or obtuse.
A triangle with two congruent sides is an isosceles triangle, and a triangle with three congruent sides is an equilateral triangle.
Perpendicular lines intersect at a 90 degree angle. Parallel lines do not intersect, nor would they ever intersect if continued infinitely.
A triangle can be Acute, Obtuse, or Right, depending on the angle. It can be Scalene, Isosceles, or Equilateral, depending on the length of the sides.
ISN and TSW
TSN and ISW
true
No, it could not. A triangle cannot have a perimeter of length zero.
JM
