0
Warren Thiel ∙
x2 - 83x + 82 = x2 - 82x - x + 82 = x(x-82)-1(x-82) = (x-1)*(x-82)
The length of arc ACB is 57.2.
55 = 40%
x = 100%
x = (55x100) ÷ 40
x = 137.5
50 degrees
35 degrees :)
41.87
45 degrees :)
BG
110
55
5.23
32 degrees
21 degrees
40
find the area of the shaded sector 12cm and 24°
30
z = 0.5244, approx.
100
120 x 130 = 15600
88 x 1.78 = (88 x 178)/100 = 15664/100 = 156.64
A+ answer is 20
80
A+ = 90
20 is the answer A+
5
The 3rd arc of the circle: 360-120-130 = 110 degrees