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if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
4x-2y
The slope is zero.
Convert the equation 2y = 5x - 4 into standard form then y = 2.5x - 2.
Two straight lines are perpendicular if the product of their gradients is -1.
Let the equation of the perpendicular line by y = mx + b. Then, 2.5m = -1 : m = -1/2.5
The y intercept occurs when x = 0. Then -3 = 0 + bc : b = -3
The equation of the perpendicular line is y = -1/2.5x -3 or 5y = -2x -15
Point (1,4) is NOT on the line x + 2y = 5
Ordered pairs are not specified.
if it is like (0,5),(0,1),(0,0),.... then we may find the answer, which then shows the family of different lines according to ordered pairs.
type the equation that shows the relationship between the variables in this chart.
(6x - 5y) + (-3x - 4y) =
6x - 5y - 3x - 4y =
3x - 9y =
3 (x - 3y)
X = 135 and y = 15
Solved by addition and substitution
An ordered pair that has a negative x-coordinate and a positive y-coordinate (-,+) would be plotted in which quadrant?
neither
(4,1) and (20, y)
They are parallel straight lines,
1
Expression.
No.
As stated these are not lines, but just a collection of algebraic terms. If we change them to y=2x and y=2x-1, then on a graph of y versus x, these are parallel lines separated by vertical distance of 1.
If you mean x+2y = 5 then yes
-2x + 2y = 4 is equivalent to twice -2 + y = 2 which is the equation of a straight line.
From a rough sketch they appear to be parallel lines but for a more accurate answer plot the points on the Cartesian plane
(f+g)(x)=8x^2+4x-4
