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☆☆☆☆☆2x / (y-2) + 2x / (2-y)
First get a common denominator: (y-2) (2-y)
Then you have:
2x(2-y) / (y-2)(2-y) + 2x(y-2) / (y-2)(2-y), summing and simplifying, you get:
(4x-4) / (y-2)(2-y)
2y = 8
y = 4 this is the equation of a horizontal line. The slope is 0, and the y-intercept is 4.
100.47
4x-2y
x + 2y = 7
2y = -x + 7
y = -(x-7)/2 => -x/2 + 7/2
2x - y = 7
-y = -2x + 7
y = 2x + 7
Since -1/2 is the negative reciporical of 2, the slopes of these equations are perpendicular. Therefore, these two lines are perpendicular.
The slope is zero.
3a + 2b = 4
If b = 7, then
3a + 2(7) = 4
3a + 14 = 4
Subtract 14 from each side:
3a = -10
Divide each side by 3:
a = -10/3
y-2x=3
-y -y
-2x=3-y
-3 -3
-2x-3=-y
/-1 /-1
2x+3=y
y=2x and y=2x+3 have the same slope of 2, so they are parallel.
Hope this helps! ;D
Convert the equation 2y = 5x - 4 into standard form then y = 2.5x - 2.
Two straight lines are perpendicular if the product of their gradients is -1.
Let the equation of the perpendicular line by y = mx + b. Then, 2.5m = -1 : m = -1/2.5
The y intercept occurs when x = 0. Then -3 = 0 + bc : b = -3
The equation of the perpendicular line is y = -1/2.5x -3 or 5y = -2x -15
perpendicular
If the original line has the equation 2y = 7x then this can be written as y = 3.5x and the slope of this line is thus 3.5.
Two straight lines are perpendicular if the product of their gradients is -1.
Let m be the slope of the perpendicular line then, 3.5m = -1 : m = -1/3.5 = -2/7
The equation of the perpendicular line is thus, y = -2/7 * x + b where b is the intercept. As b = 5 then the equation becomes y = -2/7*x + 5
We can multiply by 7 to eliminate the fraction, 7y = -2x + 35
and re-order the terms to become 7y = 35 - 2x
-2X + 2Y = 4
2Y = 2X + 4
Y = X +2
by inspection, 2
but, you could also 0 out X in original equation
-2(0) + 2Y = 4
2Y = 4
Y = 2
parell
They are parallel straight lines,
2
It is not one, but they are two perpendicular lines.
perpendicular
1
Expression.
Points: (10, 8) and (15, 8)
Slope: 0
It will be a straight horizontal line
n + 2n = 3n
As stated these are not lines, but just a collection of algebraic terms. If we change them to y=2x and y=2x-1, then on a graph of y versus x, these are parallel lines separated by vertical distance of 1.
-2x + 2y = 4 is equivalent to twice -2 + y = 2 which is the equation of a straight line.
From a rough sketch they appear to be parallel lines but for a more accurate answer plot the points on the Cartesian plane
