People aren't always exactly X feet high. For example, I am a few inches above 5 feet. It would be too obnoxious to say 5 feet 30 centimeters.
Pretty short - the current height minimum for both men and women for Navy enlistment is 51" (4'3").Of course the requirement is taller for the Army and Marines; they want people to at least be taller than the packs they're carrying.
Gheorge Muresan, at 7'7"Manute Bol as 7'6" but had a wingspan of 8'6"!The tallest current NBA player is Yao Ming at 7'6".http://www.jetpunk.com/quizzes/tallest-nba-players-quiz.phpTwo men are the answer to this list. Manute Bol and Gheorge Murasean. Both men are 7'7".
Yes - the current height/weight requirements for Navy men and women is: Minimum height (Both) 51" (4'3") Weight (Max) Men 97lbs, Women 102lbs Maximum height (Both) 86" (6'8") Weight (Max) Men 271lbs, Women 263lbs
It would help if you checked that the question made some sense before posting it!
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Probably height in inches and length in feet. Although, personally, I'd use metres for both.
The radius is 3 inches pi*32*height = 271.4 cubic inches Divide both sides by pi*9 to find the height: height = 9.598811457 or about 9.599 inches
Area = 1/2*13*height = 104 Multiply both sides by 2: 13*height = 208 Divide both sides by 13: height = 16 inches Check: 1/2*13*16 = 104 square inches
1/2*(sum of parallel sides)*height = 94.5 1/2*21*height = 94.5 sq inches Multiply both sides by 2 and then divide both sides by 21: height = 9 inches Check: 1/2*21*9 = 94.5 sq inches
Volume: pi*122*height = 3754.8 Divide both sides by pi*12 squared: height = 8.299930282 or about 8.3 inches
It's called volume I think.
No, but both are used to measure distance.
All of them.
Standing height 64 inches minimum to 77 inches maximum for both pilot and navigator qualification. Sitting height 34 inches minimum (pilot) and 33 inches minimum (navigator) to 40 inches maximum (both), measured while sitting erect, the distance from top of head to chair seat.
the average height for both girls and boys at the age of 3 is 33 inches.
Not necessarily. You find the area of a triangle with the formula 1/2*base*height=Area. Imagine two triangles, one with 3 inches for both the base and height, and one with 4.5 inches for the height and 2 inches for the base. Both of these triangles will have 9 sq. in. for their areas, but they are not congruent.
Depends on the shape of the area. For a rectangle the answer is the width * the height, assuming both measurements are in inches.