Wiki User
∙ 16y ago52.38% Increase
Wiki User
∙ 16y agoPercentage increase = 100*(new value-old value)/old value = 100*(72-57)/57 = 100*15/57 = 1500/57 = 26.3 %
-- If it's an increase, thenNext year = (This year) x (0.01) x (100 + the percent increase).-- If it's a decrease, thenNext year = (This year) x (0.01) x (100 - the percent decrease) .
"Output per work is expected to increase by 10 percent during the next year. Therefore, wage can also increase by 10 percent with no harmful effects on employment, output prices, or employer profits." Discuss this statement. "Output per work is expected to increase by 10 percent during the next year. Therefore, wage can also increase by 10 percent with no harmful effects on employment, output prices, or employer profits." Discuss this statement. "Output per work is expected to increase by 10 percent during the next year. Therefore, wage can also increase by 10 percent with no harmful effects on employment, output prices, or employer profits." Discuss this statement. "Output per work is expected to increase by 10 percent during the next year. Therefore, wage can also increase by 10 percent with no harmful effects on employment, output prices, or employer profits." Discuss this statement.
-- To get next year's value, multiply this year's value by 1.02 -- Then, to get the amount of the increase, subtract this year's value from the result.
2000/18000 x 100 = 11.1%
5% The difference in enrollment is 28 students. 28/560 = 0.05 You use 560 because that was the ORIGINAL enrollment.
168270
376*40=150.40 150.40=150 Answer: 150 students
The increase in population was 126 students (1926 - 1800 = 126). To find the percentage increase, divide the increase by the original population (126 / 1800 = 0.07). Convert this to a percentage by multiplying by 100, so the population increased by approximately 7%.
The school saw a decrease in students of 18.3801%
Tina's pay increase was 9.828% (10% to nearest percent).
The graduation rate of Purchase college is forty four percent for four year students and fifty six percent for six year students.