522 matches in a minimum of 10 rounds. *The number of rounds required for from 512 to 1023 players is 10 rounds (512 = 29)
n(n-1)/2
8 matches .. as from 9 teams only 1 will win , rest 8 teams must lose , in knockout tournament 1 team goes out in 1 match .
77
kenya
Assuming that a knock out is a single elimination tournament, where each player/team plays until they lose, there are 38 games. Only one team will not lose.
The amount of players in a poker tournament varies from tournament to tournament. For example the poker games played in Vegas accommodate two to approximately sixteen people.
Well here's what I got: 64 divided by 2= 32*6 matches for a games= 192 matches...... that's if the players play 6 matches for one whole game.... and how many times can they play and lose 'till they get out completely??? If it's different then I would need more information to answer this question
If you have 20 players in a tournament with single elimination, you will have to play 19 games...
65
i think it is 132 matches but im not sure.
22
Gary speed