this cube is cut into 64 equal pieces....................................asdflkasufoiwerflkasdjf;laskudof
Coal cubes: 0. Sugar cubes: 0 Painted cubes: maybe some of them.
Only the 8 corner cubelets of the original large cube will have three painted faces.
0 sides are not painted! So all the cubes have three faces painted!
How many smaller cubes are not painted at all if a cube is painted green on all sides & cut into 64 cubes of equal size?
0 - you said it's only 1 cube even if it's a big one
A 5x5x5 cube consists of 125 smaller unit cubes. When painted on the outside, the cubes on the surface are affected, while those entirely inside remain unpainted. To find the number of painted and unpainted cubes, you can calculate the number of cubes on the surface and subtract the volume of the inner 3x3x3 cube (which contains 27 unit cubes) from the total. Thus, the painted cubes are 125 - 27 = 98, while the unpainted cubes remain 27.
When a solid wooden cube is painted blue and then cut into 27 smaller cubes, the original cube's surface area is divided among the smaller cubes. Since each side of the larger cube is painted, the outer layer of the smaller cubes will be blue. Out of the 27 smaller cubes, only the 8 cubes in the center do not have any blue paint, while the remaining 19 have at least one face painted blue. Therefore, the fraction of the total surface area that is blue is ( \frac{19}{27} ).
It depends on how the rectangular solid is built. If the side of a cube is "a", then your original solid could be a x a x 54a, or a x 2a x 27a, or 2a x 3a x 9a or one of quite a few others, and the answer depends on the one you specify.
I am assuming that your question states that the top and sides are painted red but the bottom isn't. If so, the answer is:- There are no cubes with 4 faces painted, the most that can be painted is 3 for the ones on the corners. There are 4 corners at the top of the cube that will have their top and 2 sides painted. Therefore there are 4 cubes with 3 painted. The cubes at the corners on the second and third row down will have 2 faces painted, as will the middle cubes on the top row so there are 12 of them in this puzzle. The cube in the middle of each painted face will have just one face painted so this is 5 (assuming the bottom isn't painted). The cubes in the middle of the bottom row will also have one face painted. This brings the total to 9 That is the total of cubes that have paint on them... 4+12+9 = 25 There are 27 cubes in your puzzle so only 2 have no painted faces. The cube right in the middle and the cube in the middle of the bottom layer.
When a cube is painted on all six faces and then sliced into 27 smaller cubes (which creates a 3x3x3 arrangement), the smaller cubes that are painted on only one face are those located in the center of each face of the larger cube. There are 6 faces on the cube, and each face has 1 center cube that is painted only on one side. Therefore, there are a total of 6 smaller cubes that are painted on only one face.
Answer = 8. The only small cubes with paint on three faces are those that occupied the corners of the original cube.
All the little cubes except the one at the middle will have 1, 2 or 3 faces with paint on them, ie 26 of them will have some paint on them: 0 faces painted - 1 cube 1 face painted - 6 cubes (the centre ones of each side) 2 faces painted - 12 cubes (the ones in the centre of where two sides meet) 3 faces painted - 8 cubes (the ones in the corners).