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An object with a mass of 21kilograms is lifted through a distance of 7 meters How much work is done?
Wiki User
∙ 14y ago
use the formula W = mgs
W stands for work done in joules
m stands for mass of the object
g stands for gravity
s stands for the distance the object is lifted
W = mgs
W = 78kilograms•9.8m/s2•6meters
W = 4586.4 J (joules) answer would be 4,586.4 J
Wiki User
∙ 16y ago
Wiki User
∙ 10y agoAn object with a mass of 78 kilograms is lifted through a height of 6 meters. How much work is done?
Wiki User
∙ 14y agoit is impossible to know you have to give a velocity to get its momentum otherwise you cannot determine this answer.
Wiki User
∙ 14y agothe answer is -D. 1,440.6 (I just took the test) :)
Wiki User
∙ 14y agoC. 1,440.6 j
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An object with a mass of 21 kilograms is lifted through a distance of 7 meters How much?
question 24 on penn foster is C.
You use an incline plane to lift a car up 4 meters is the distance of effort or distance of resistance?
The distance of effort is the distance along the incline plane that you apply force to lift the car. The distance of resistance is the vertical distance that the car is being lifted. In this scenario, the distance of effort is the 4 meters along the incline plane, and the distance of resistance is the vertical height the car is lifted.
What is the potential energy of a crate lifted with a force of 100 newtons a vertical distance of 2 meters?
Force x distance = 100 x 2 = 200 newton-meters = 200 joules.
What is the answer if A fallen tree is lifted 2.75 meters How much work is done?
The work done on the fallen tree would depend on the force applied, not just the distance lifted. Work is calculated as force multiplied by distance. Without knowing the force applied, we cannot determine the work done.
A force of 100 N was necessary to lift a tree. A total of 150 Joules of work was done. How far was the tree lifted?
To find the distance the tree was lifted, we can use the formula for work: Work = Force x Distance. Given that 150 Joules of work was done and the force was 100 N, we can rearrange the formula as Distance = Work / Force. Plugging in the values, we get Distance = 150J / 100N = 1.5 meters. Therefore, the tree was lifted 1.5 meters.
A crane does work at 13500 Jay with a force the 5200 n to list a bean how far can the bean be listed in meters?
The question seems to be missing some information required to calculate the distance the bean can be lifted by the crane. We would need the height the bean needs to be lifted to determine the distance in meters.
How much work is done when 700 n object is lifted straight up a distance of 4 meters?
700 x 4 = 2,800 newton-meters = 2,800 joules
How much work is done if a fallen tree is lifted 2.75 meters?
The work done in lifting the tree is equal to the force applied multiplied by the distance it is lifted. The amount of work done would depend on the weight of the tree and the force required to lift it to a height of 2.75 meters above the ground.
How much work is done when a 700 n fridge is lifted straight up a distance of 4 meters?
The work done in lifting the fridge is equal to the force applied (700 N) multiplied by the distance moved (4 meters), which gives a total work of 2800 joules.
How much work is done when a 1 newton book is lifted 2 meters?
The work done is 2 joules. Work is calculated by multiplying the force exerted (1 newton) by the distance moved in the direction of the force (2 meters).
An object of mass 4.5 is lifted through a distance of 10m H ow much work is done?
The work done is given by the formula: work = force x distance. Since the force required to lift an object against gravity is equal to its weight (mass x gravity), the work done is 4.5 kg x 9.8 m/s^2 x 10 m = 441 J.
What is the equation for finding distance lifted when force and mass are given?
The equation for finding distance lifted when force and mass are given is: distance lifted = (force * distance)/ mass * gravity, where force is the applied force, mass is the mass of the object being lifted, distance is the vertical distance lifted, and gravity is the acceleration due to gravity (9.81 m/s^2).
