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A vehicle travels approximately 1.5 ft per second for each mile per hour. 25 x 1.5 = 37.5. Add to that the average human response time to react to stimuli and apply the brake (1.5 sec again) = 56.25 ft before the vehicle begins to stop.

Braking on most surfaces slows you 15 feet per second, per second of braking.

37.5 fps to 0 fps = 2.5 sec to stop

(37.5 fps/2) x 2.5 sec = 46.875 ft braking distance +56.25 reaction distance

= 103.125 ft between recognition of a danger and your vehicle stopping.

Add to that the braking efficiency of the vehicle. You can also account for the drag coefficient of the pavement and grade (.7 to .8)but that is usually a negligible amount unless you are doing serious traffic crash reconstructions.

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βˆ™ 12y ago
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βˆ™ 11y ago

228 feet

One foot. Your foot on the brake. Sorry, I couldn't resist. That answer is absolutely correct

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βˆ™ 11y ago

a round 62 feet

One foot planted firmly on the brake pedal
That depends on the mass of the car, and the composition and condition of the pavement.

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βˆ™ 14y ago

You should memorize 60 mph = 88 feet per sec. Then (25 mph)/(60 mph)*(88 feet/sec) = 36.6666.... feet per second

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βˆ™ 14y ago

Stopping distance for a car travelling at 25mph is 38 feet, you would need to add a reaction time (the time between when you see the need to stop and you react by appling the brakes)

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βˆ™ 14y ago

228 ft

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Q: How many feet per second at 25 mph?
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