200Nm 2000Nm work = force X distance (Nm) note Force = Weight, the have the same units SI
faggio
200 newton-meters per second = 200 watts.
A pulley system is used to lift a 2,000 newton engine up a distance of 3 meters. How much force will the operator have to apply if the mechanical advantage of the pulley system is 4? mechanical advantage = 500 newtons.
20
The work done to lift the log can be calculated using the formula: Work = Force x Distance. In this case, the force is 5000 N and the distance is 5 meters. Therefore, the work required to lift the log 5 meters would be 5000 N x 5 m = 25000 Joules.
Power = (energy) / (time) =(200 newtons x 4 meters) / (4 seconds) =200 newton-meters per second = 200 watts
140 ft-pounds is equivalent to approximately 190 Newton meters.
10 METERS
The work done is 2 joules. Work is calculated by multiplying the force exerted (1 newton) by the distance moved in the direction of the force (2 meters).
Work = force x distance = (4 x 10) = 40 newton-meters = 40 joules
1 newton-meter = 1 joule
koalas weight is 19.8 pounds