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How many 8 ft boards needed for a frame 3x4 with a diagonal?
To create a frame measuring 3 feet by 4 feet with a diagonal, you will need to calculate the perimeter and add the diagonal length. The perimeter of the rectangle is 2(3 + 4) = 14 feet. The diagonal can be calculated using the Pythagorean theorem: √(3² + 4²) = 5 feet. Therefore, the total length needed is 14 + 5 = 19 feet. Since each board is 8 feet long, you will need 3 boards (2 for the perimeter and 1 for the diagonal).
How long is the diagonal of a rectangle with demensions 42ft by 25?
The diagonal is 48.877 feet.
8 feet long and 9 feet long what is the perimeter?
If the given dimensions are that of a rectangle then perimeter is: 34 feet
How long is the diagonal of a rectangle with dimensions 50 feet by 125 feet?
134.6 feet
A rectangle is 90 inches long and 66 inches wide what is the perimeter of the rectangle in feet?
26 feet.
How long is the diagonal of a rectangle 70' x 77'?
104.1 feet
How long is diagonal of 26x36 rectangle?
44 feet 4 inches
What is the perimeter for a rectangle that is 9 feet long and 4 feet wide?
perimeter of a rectangle is 2*( length +breadth)= 2*(9+4)= 26 feets
What is 12 feet long and 6 feet wide what is the perimeter?
It is a rectangle and its perimeter is 12+12+6+6 = 36 feet
If a rectangle is 45 feet long and 30 yards wide what is the perimeter in feet?
270 feet.
What is the length of diagonal line in a rectangle 12 feet long and 10 feet wide?
Approximately 15.62 feet.
What is the perimeter of a rectangle is 20 feet and the area is 24 square feet What is the width of the rectangle?
The rectangle is 6-ft long and 4-ft wide.
