There are an infinite number of (x,y) pairs that satisfy the equation.
Here are a few of them:
X . . Y
-4 . . 6
-3 . . 5
-2 . . 4
-1 . . 3
0 . . . 2
1 . . . 1
2 . . . 0
3 . . . -1
4 . . . -2
Since there are two variables, it takes two equations to pin them down.
Transitive property: If 8 equals x and x equals y, then 8 equals y.
x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32
x=4 y=4
x = 8 and y = 0
8
Transitive property: If 8 equals x and x equals y, then 8 equals y.
x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32
x=4 y=4
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
x = 8 and y = 0
8
x + y = 10 y = x + 8 so, x + (x + 8) = 10 2x + 8 = 10 2x + 8 - 8 = 10 - 8 2x = 2 x = 1 and y = 9 because y = x + 8 y = 1 + 8 y = 9
xy = 8 or y = 8/x
x=y-8 z=x+12
y=8 y = 2x y = 2(4) <-- substitute 4 for x y = 8 <-- this is your answer
y is 12
8