10x+7 = 5x+32 10x-5x = 32-7 5x = 25 x = 5
If: 10x+7 = 5x+22 Then: 10x-5x = 22-7 And: 5x = 15 So: x = 3
DIE
5x + 7 = 4subtract 7 from both sides5x = -3divide both sides by 5x = -3/5
3x - 7 = 5x + 133x - 5x = 13 + 7-2x = 20x = -10x=-3
If: 5x = 4x+7 Then: 5x-4x = 7 And: x = 7
8x-7 plus 2x equals 6 plus 5x plus 2?
10x+7 = 5x+32 10x-5x = 32-7 5x = 25 x = 5
If: 10x+7 = 5x+22 Then: 10x-5x = 22-7 And: 5x = 15 So: x = 3
To evaluate the algebraic expression 7 + 5x for x = 10, you substitute the value of x into the expression. So, you get 7 + 5(10), which simplifies to 7 + 50. Therefore, the final answer is 57.
DIE
-6x+3 = -7-5x 7+3 = 6x-5x 10=x
3x + 2 + 2x = 7; 3x + 2x = 5x, so 5x + 2 = 7; 7-2=5, so 5x=5. 5x divided by 5 and 5 divided by 5 equals 1, so x equals 1.
It is: y = -1/5x+7 that is perpendicular to y = 5x+7
5x + 7 = 4subtract 7 from both sides5x = -3divide both sides by 5x = -3/5
3x - 7 = 5x + 133x - 5x = 13 + 7-2x = 20x = -10x=-3
If: x = 7 Then: y = (2*7)+3 = 17 And: 5x+y = (5*7)+17 = 52