The square root of 121 is 11 and 11 plus 49 = 60
9y2+66y+121 = (3y+11)(3y+11) when factored
(2y-11)^2
We're given: 9x + 2x = 121 The first step is to group like terms on the left: (9 + 2)x = 121 11x = 121 Now divide both sides by 11: 11x/11 = 121/11 x = 11
Because (+11) * (+11) = +121 AND (-11) * (-11) = +121
The square root of 121 is 11 and 11 plus 49 = 60
9y2+66y+121 = (3y+11)(3y+11) when factored
100v2 - 220v + 121 = (10v - 11)2
The GCF is 11.
It is: 36 plus 121 = 157
Expand z plus 11 times z plus 11 = (z+11)(z+11) = z2 + 22z + 121.
(2y-11)^2
x2 - 22x + 121 = (x - 11)2
We're given: 9x + 2x = 121 The first step is to group like terms on the left: (9 + 2)x = 121 11x = 121 Now divide both sides by 11: 11x/11 = 121/11 x = 11
42 + 79 = 121 (40+70) + (2+9) = = 110 + 11 = 121
√121 = 11 → 11 × 11 = 121 Also: -11 × -11 = 121
The factors of 121 are 1•121 and 11•11 :)