You have to setup two different equations first. One to get the total number of animals and another to get the total number of feet.
Since all the chickens plus all the rabbits equals 105 animals, c + r = 105.
Since chickens have two feet and rabbits have four feet with the given total as 360, 2c + 4r =360.
Then we will define the first equation in terms of "r" by finding the value for "c" in the second equation.
2c + 4r = 360
2c = 360 - 4r
c= 180 -2r
Now we will substitute this value for "c" into the first equation.
c + r = 105
(180 - 2r) + r = 105
180 - r = 105
r = 75
So, there are 75 rabbits. Then to find the number of chickens, we plug in the numerical value for "r" in the first equation.
c + r = 105
c + 75 = 105
c = 30
There are 75 rabbits and 30 chickens. This equals 105 animals with a combined total of 360 feet.
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Do-it-in-your-head method: If all animals were chickens there would be 90 legs. There are 20 extra legs, each on a cow, so there are 20 cows and therefore 25 chickens.
3 Sheep 15 = 45 41 Chickens @ 1.00 = 41 56 Mice @ .25 = 14
if he has 100 dollars, and can only buy 100 animals, then he can buy 76 chickens for $38, 21 Pigs for $42, and 4 sheep for $20. :) well that's 101, but im close. and i did it all by myself. :D
Let x = the number of goats (4 legs) 4x = the number of chickens (2 legs) So we have 4*x + 2*4x = 144 4x + 8x = 144 12x = 144 x = 144/12 = 12 (goats and 48 chickens) or Let's suppose that each of them have 6 legs, so there would be 24 chickens and goats (144/6), and we can say there are 12 chickens and 12 goats. But the number of chickens is 4 times the number of goats, so there are 48 chickens (4*12) and 12 goats.
There are 139 chickens and 30 pigs. Let c = number of chickens and p = number of pigs Each has 1 head, therefore c + p = 169 Each chicken has 2 feet and each pig has 4 feet, therefore 2c + 4p = 398 => c + 2p = 199 Subtracting the first from the second gives: c + 2p - c - p = 199 - 169 => p = 30 Substitute in the first c + 30 = 169 c = 139