77040
77,040 because 107 x 2 = 214 214 x 3 = 642 642 x 4 = 2568 2568 x 5 = 12840 12840 x 6 = 77040
Each number is multiplied by an incrementing value. 107 is multiplied by 2, 214 is multiplied by 3, 642 is multiplied by 4 and so on.
The first 15 multiples of 107: 107, 214, 321, 428, 535, 642, 749, 856, 963, 1070, 1177, 1284, 1391, 1498, 1605 . . . ∞
107
77040
77,040 because 107 x 2 = 214 214 x 3 = 642 642 x 4 = 2568 2568 x 5 = 12840 12840 x 6 = 77040
If the fourth term were 2568 there is a simple answer, but with the series going up and down, I have no clue.
77,040 That is correct, because... 107 x 2 = 214 214 x 3 = 642 642 x 4 = 2568 2568 x 5 = 12840 12840 x 6 = 77040
77040
77,040
Each number is multiplied by an incrementing value. 107 is multiplied by 2, 214 is multiplied by 3, 642 is multiplied by 4 and so on.
multiply by 1 higher number each time 214 / 107 = 2 642 / 214 = 3 2,568 / 642 = 4 12,840 / 2,568 = 5 so 6 x 12,840 = 77,040 next
The next number is 77040. Solution: 107 x 2 = 214x 3 = 642 x 4 = 2568 x 5 = 12840 x 6 = 77040
77040. It goes like, 107 * 2 = 214 214 * 3 = 642 642 * 4 = 2568, and so on. x * a(+1) = (a new)x Except that the word "completes" would suggest that there are no more terms. Not true!
642 is composite. It is divisible by 2, 3, 107, 214, and 321.
1, 2, 3, 6, 107, 214, 321, 642 2, 3 and 107 are prime.