10 coins are tossed once .The probalilty of getting exactly eight heads is?

Answer 1

The probability of getting 8 heads out of 10 tosses is (10C8)(1/2)^8 (1/2)^2 = 45 / 1024 = 0.0439.

It is assumed that the probability of getting a head in a single toss is 1/2.

10C8 = 10 x 9 / 1 x 2 = 45

Answer 2

The probability of getting exactly eight heads when tossing 10 coins once can be found using the binomial probability formula. Assuming a fair coin, the probability of getting a heads is 1/2. Plugging in the numbers, the probability of getting exactly eight heads is (10 choose 8) * (1/2)^8 * (1/2)^2 = 45/1024, which is approximately 0.04395.