116 Years in the Hundred Years' War.
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if x + y = w, then x = w - y
x - y = w Add y to both sides: x = w + y
You can set this problem up like this: 48/4 = y/11 Cross multiply 48*11 = 4y 528 = 4y 528 divided by 4 = 132 So when w equals 11 y equals 132
10*6+8*7 = 116
8x - y = 31 <=> y = 8x - 31. 5x + 3y = 23 => 5x + 3 * (8x - 31) = 23 <=> 5x + 24x - 93 = 23 <=> 29x = 23 + 93 <=> 29x = 116 <=> 29x/29 = 116/29 <=> x = 4. y = 8x - 31 => y = 8 * 4 - 31 <=> y = 32 - 31 <=> y = 1.