4Σ (12 - 4i)i=0
18 + 12 + 0 - 4 - 10 = 16
8 plus 4 minus 12 divided by 1 is 0.
(x + 3)(x + 4) x = -3, -4 Check it. 9 - 21 + 12 = 0 16 - 28 + 12 = 0 It checks.
1 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 12 + 133 + 4 = 195
4Σ (12 - 4i)i=0
18 + 12 + 0 - 4 - 10 = 16
8 plus 4 minus 12 divided by 1 is 0.
(x + 3)(x + 4) x = -3, -4 Check it. 9 - 21 + 12 = 0 16 - 28 + 12 = 0 It checks.
(x + 3)(x + 4)
You can't add them together because they are not like terms (there are 5 different variables) You can only define each variable in terms of the others. This is a linear equation in 5 variables, so we can say that the given statement is true if we can solve the equation, that is if we can find values for the variables that satisfy the equation. Solutions are points of the form (x, y, z, s, t) which can exist in 5D. We can say that there are infinitely many solutions. Let's find 5 solutions: (87, 0, 0, 0, 0) (0, 87/2, 0, 0, 0) (0, 0, 29, 0, 0) (0, 0, 0, 87/4, 0) (0, 0, 0, 0, 87/5) We cannot visualize things in 5D, but sometimes we like to say that these 5 points can determine a hyper-plane there. Each solution set is the intercept for one of the 5 perpendicular axes.
1 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 12 + 133 + 4 = 195
x2-7x+12 = 0 (x-3)(x-4) = 0x=3,4
For it to have two equal roots then the discriminant of the quadratic equation must equal zero:- 242-4*(b) = 0 576 -4*(b) = 0 -4*(b) = -576 Divide both sides by -4 to find the value of b: b = 144 So the quadratic equation is: x2+24x+144 = 0 When factored: (x+12)(x+12) = 0 Therefore: x = -12 or x = -12
-8z + 12 = 12 - 4z-8z +4z + 12 = 12 - 4z +4z-4z + 12 -12 = 12 -12-4z / -4 = 0 / -4z = 0:)
simply 9
x=27