28y - 16y = 12y.
-3x+16y = 28 3(x-3y = 7) Multiply the bottom equation by 3 then add both equations together in order to eliminate x: 7y = 49 y = 7 Substitute the value of y into the original to find the value of x: So: x = 28 and y = 7
The equation does not represent that of a parabola.
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Point of contact: (21, 8) Equation of circle: x^2 -y^2 -8x -16y -209 = 0 Completing the squares: (x-4)^2 +(y-8)^2 = 289 Centre of circle: (4, 8) and its radius is 17 Slope of radius: 0 Slope of tangent: 0 Tangent equation of the circle: x = 21 meaning that the tangent line is parallel to the y axis and that the radius is parallel to the x axis.
Find the value of y in this equation: 16y = 164.Answer: 10 1/4
16y = 164 y = 164/16 = 82/8 = 41/4 = 10.25
28y - 16y = 12y.
-3x+16y = 28 3(x-3y = 7) Multiply the bottom equation by 3 then add both equations together in order to eliminate x: 7y = 49 y = 7 Substitute the value of y into the original to find the value of x: So: x = 28 and y = 7
The equation does not represent that of a parabola.
5x - 4y = -41 => 5x = 4y - 41 => x = (4y - 41)/5 Then 4x + 35 = 4*[(4y - 41)/5] + 35 = 16y/5 - 164/5 + 35 = 16y/5 -11/5 or (16y - 11)/5
This is a simultaneous equation question. 4(3x+4y = 90) 3(4x-3y = -5) Multiply the top equation by 4 and the bottom equation by 3 then subtract the bottom equation from the top equation remembering that in maths a minus from a minus is equal to a plus. 12x+16y = 360 12x-9y = -15 And when subtracted: 0+25y = 375 Divide both sides of the equation by 25 to find the value of y: y = 15 Substitute 15 for y into the original equation to find the value of x: Solution: x = 10 and y = 15
It is: 28y -16y = 12y
It is: 28y -16y = 12y
16y -64 as an inequality = -48
x² + y² = 9/16 or 16x² + 16y² = 9
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